← numpy-100

Replaced README with index such that page can be read directly from github

c91be62ff4af1e1e67d299550e93d3e8f9a7a1fc · Nicolas Rougier · May 27, 2014 06:15

−506 · 1 file changed

  • index.rst +0 −506
diff --git a/index.rst b/index.rst
deleted file mode 100644
index 033fe22..0000000
--- a/index.rst
+++ /dev/null
@@ -1,506 +0,0 @@
-===================
-100 numpy exercises
-===================
-
-A joint effort of the numpy community
--------------------------------------
-
-The goal is both to offer a quick reference for new and old users and to
-provide also a set of exercices for those who teach.
-
-If you remember having asked or answered a (short) problem, you can send a pull
-request. The format is:
-
-
-#. Find indices of non-zero elements from [1,2,0,0,4,0]
-
-   .. code:: python
-
-      # Author: Somebody
-
-      print np.nonzero([1,2,0,0,4,0])
-
-
-If you can provide the assumed level of the answer, that would be even better.
-
-Here is what the page looks like so far:
-
-http://www.loria.fr/~rougier/teaching/numpy.100/index.html
-
-(The level names came from an old-game: Dungeon Master)
-
-
-
-.. contents::
-   :local:
-   :depth: 1
-
-
-Neophyte
-========
-
-1. Import the numpy package under the name ``np``
-
-   .. code:: python
-
-      import numpy as np
-
-
-#. Print the numpy version and the configuration.
-
-   .. code:: python
-
-      print np.__version__
-      np.__config__.show()
-
-
-#. Create a null vector of size 10
-
-   .. code:: python
-
-      Z = np.zeros(10)
-
-#. Create a null vector of size 10 but the fifth value which is 1
-
-   .. code:: python
-
-      Z = np.zeros(10)
-      Z[4] = 1
-
-#. Create a vector with values ranging from 10 to 99
-
-   .. code:: python
-
-      Z = np.arange(10,100)
-
-#. Create a 3x3 matrix with values ranging from 0 to 8
-
-   .. code:: python
-
-      Z = np.arange(9).reshape(3,3)
-
-#. Find indices of non-zero elements from [1,2,0,0,4,0]
-
-   .. code:: python
-
-      nz = np.nonzero([1,2,0,0,4,0])
-
-
-#. Declare a 3x3 identity matrix
-
-   .. code:: python
-
-      Z = np.eye(3)
-
-#. Declare a 5x5 matrix with values 1,2,3,4 just below the diagonal
-
-   .. code:: python
-
-      Z = np.diag(1+np.arange(4),k=-1)
-
-
-#. Declare a 10x10x10 array with random values
-
-   .. code:: python
-
-      Z = np.random.random((10,10,10))
-
-Novice
-======
-
-#. Declare a 8x8 matrix and fill it with a checkerboard pattern
-
-   .. code:: python
-
-      Z = np.zeros((8,8))
-      Z[1::2,::2] = 1
-      Z[::2,1::2] = 1
-
-#. Declare a 10x10 array with random values and find the minimum and maximum values
-
-   .. code:: python
-
-      Z = np.random.random((10,10))
-      Zmin, Zmax = Z.min(), Z.max()
-
-#. Create a checkerboard 8x8 matrix using the tile function
-
-   .. code:: python
-
-      Z = np.tile( np.array([[0,1],[1,0]]), (4,4))
-
-#. Normalize a 5x5 random matrix (between 0 and 1)
-
-   .. code:: python
-
-      Z = np.random.random((5,5))
-      Zmax,Zmin = Z.max(), Z.min()
-      Z = (Z - Zmin)/(Zmax - Zmin)
-
-
-#. Multiply a 5x3 matrix by a 3x2 matrix (real matrix product)
-
-   .. code:: python
-
-      Z = np.dot(np.ones((5,3)), np.ones((3,2)))
-
-
-#. Create a 10x10 matrix with row values ranging from 0 to 9
-
-   .. code:: python
-
-    Z = np.zeros((10,10))
-    Z += np.arange(10)
-
-#. Create a vector of size 1000 with values ranging from 0 to 1, both excluded
-
-   .. code:: python
-
-    Z = np.random.linspace(0,1,1002,endpoint=True)[1:-1]
-
-#. Create a random vector of size 100 and sort it
-
-   .. code:: python
-
-    Z = np.random.random(100)
-    Z.sort()
-
-#. Consider two random matrices A anb B, check if they are equal.
-
-   .. code:: python
-
-      A = np.random.randint(0,2,(2,2))
-      B = np.random.randint(0,2,(2,2))
-      equal = np.allclose(A,B)
-
-#. Create a random vector of size 1000 and find the mean value
-
-   .. code:: python
-
-      Z = np.random.random(1000)
-      m = Z.mean()
-
-
-
-Apprentice
-==========
-
-
-#. Make an array immutable
-
-   .. code:: python
-
-      Z = np.zeros(10)
-      Z.flags.writeable = False
-
-
-#. Consider a random 100x2 matrix representing cartesian coordinates, convert
-   them to polar coordinates
-
-   .. code:: python
-
-      Z = np.random.random((100,2))
-      X,Y = Z[:,0], Z[:,1]
-      R = np.sqrt(X**2+Y**2)
-      T = np.arctan2(Y,X)
-
-
-#. Create random vector of size 100 and replace the maximum value by 0
-
-   .. code:: python
-
-    Z = np.random.random(100)
-    Z[Z.argmax()] = 0
-
-
-#. Declare a structured array with ``x`` and ``y`` coordinates covering the
-   [0,1]x[0,1] area.
-
-   .. code:: python
-
-      Z = np.zeros((10,10), [('x',float),('y',float)])
-      Z['x'], Z['y'] = np.meshgrid(np.linspace(0,1,10),
-                                   np.linspace(0,1,10))
-
-#. Print the minimum and maximum representable value for each numpy scalar type
-
-   .. code:: python
-
-      for dtype in [np.int8, np.int32, np.int64]:
-         print np.iinfo(dtype).min
-         print np.iinfo(dtype).max
-      for dtype in [np.float32, np.float64]:
-         print np.finfo(dtype).min
-         print np.finfo(dtype).max
-         print np.finfo(dtype).eps
-
-
-#. Create a structured array representing a position (x,y) and a color (r,g,b)
-
-   .. code:: python
-
-      Z = np.zeros(10, [ ('position', [ ('x', float, 1),
-                                        ('y', float, 1)]),
-                         ('color',    [ ('r', float, 1),
-                                        ('g', float, 1),
-                                        ('b', float, 1)])])
-
-
-#. Consider a random vector with shape (100,2) representing coordinates, find
-   point by point distances
-
-   .. code:: python
-
-      Z = np.random.random((10,2))
-      X,Y = np.atleast_2d(Z[:,0]), np.atleast_2d(Z[:,1])
-      D = np.sqrt( (X-X.T)**2 + (Y-Y.T)**2)
-
-      # Much faster with scipy
-      Z = np.random.random((10,2))
-      D = scipy.spatial.distance.cdist(Z,Z)
-
-
-
-#. Generate a generic 2D Gaussian-like array
-
-   .. code:: python
-
-      X, Y = np.meshgrid(np.linspace(-1,1,100), np.linspace(-1,1,100))
-      D = np.sqrt(X*X+Y*Y)
-      sigma, mu = 1.0, 0.0
-      G = np.exp(-( (D-mu)**2 / ( 2.0 * sigma**2 ) ) )
-
-#. Consider the vector [1, 2, 3, 4, 5], how to build a new vector with 3
-   consecutive zeros interleaved between each value ?
-
-   .. code:: python
-
-      # Author: Warren Weckesser
-
-      Z = np.array([1,2,3,4,5])
-      nz = 3
-      Z0 = np.zeros(len(Z) + (len(Z)-1)*(nz))
-      Z0[::nz+1] = Z
-
-
-#. Find the nearest value from a given value in an array
-
-   .. code:: python
-
-      Z.flat[np.abs(Z - z).argmin()]
-
-
-
-Journeyman
-==========
-
-#. Consider the following file::
-
-    1,2,3,4,5
-    6,,,7,8
-    ,,9,10,11
-
-   How to read it ?
-
-   .. code:: python
-
-      Z = genfromtxt("missing.dat", delimiter=",")
-
-
-#. Consider a generator function that generates 10 integers and use it to build an
-   array
-
-   .. code:: python
-
-      def generate():
-          for x in xrange(10):
-              yield x
-      Z = np.fromiter(generate(),dtype=float,count=-1)
-
-
-#. Consider a given vector, how to add 1 to each element indexed by a second
-   vector (be careful with repeated indices) ?
-
-   .. code:: python
-
-      # Author: Brett Olsen
-
-      Z = np.ones(10)
-      I = np.random.randint(0,len(Z),20)
-      Z += np.bincount(I, minlength=len(Z))
-
-
-#. How to accumulate elements of a vector (X) to an array (F) based on an index
-   list (I) ?
-
-   .. code:: python
-
-      # Author: Alan G Isaac
-
-      X = [1,2,3,4,5,6]
-      I = [1,3,9,3,4,1]
-      F = np.bincount(I,X)
-
-#. Considering a (w,h,3) image of (dtype=ubyte), compute the number of unique
-   colors
-
-   .. code:: python
-
-      # Author: Nadav Horesh
-
-      w,h = 16,16
-      I = np.random.randint(0,2,(h,w,3)).astype(np.ubyte)
-      F = I[...,0]*256*256 + I[...,1]*256 +I[...,2]
-      n = len(np.unique(F))
-
-      np.unique(I)
-
-#. Considering a four dimensions array, how to get sum over the last two axis at once ?
-
-
-   .. code:: python
-
-      A = np.random.randint(0,10,(3,4,3,4))
-      sum = A.reshape(A.shape[:-2] + (-1,)).sum(axis=-1)
-
-
-
-Craftsman
-=========
-
-#. Consider a one-dimensional array Z, build a two-dimensional array whose
-   first row is (Z[0],Z[1],Z[2]) and each subsequent row is shifted by 1 (last
-   row should be (Z[-3],Z[-2],Z[-1])
-
-   .. code:: python
-
-      # Author: Joe Kington / Erik Rigtorp
-
-      def rolling(a, window):
-          shape = (a.size - window + 1, window)
-          strides = (a.itemsize, a.itemsize)
-          return np.lib.stride_tricks.as_strided(a, shape=shape, strides=strides)
-
-      Z = rolling(np.arange(100), 3)
-
-#. Consider a set of 100 triplets describing 100 triangles (with shared
-   vertices), find the set of unique line segments composing all the triangles.
-
-   .. code:: python
-
-      # Author: Nicolas Rougier
-
-      faces = np.random.randint(0,100,(100,3))
-
-      F = np.roll(faces.repeat(2,axis=1),-1,axis=1)
-      F = F.reshape(len(F)*3,2)
-      F = np.sort(F,axis=1)
-      G = F.view( dtype=[('p0',F.dtype),('p1',F.dtype)] )
-      G = np.unique(G)
-
-
-
-Artisan
-=======
-
-#. Considering a 100x3 matrix, extract rows with unequal values (e.g. [2,2,3])
-
-   .. code:: python
-
-      # Author: Robert Kern
-
-      Z = np.random.randint(0,5,(100,3))
-      E = np.logical_and.reduce(Z[:,1:] == Z[:,:-1], axis=1)
-      U = Z[~E]
-
-#. Convert a vector of ints into a matrix binary representation.
-
-   .. code:: python
-
-      # Author: Warren Weckesser
-
-      I = np.array([0, 1, 2, 3, 15, 16, 32, 64, 128])
-      B = ((I.reshape(-1,1) & (2**np.arange(8))) != 0).astype(int)
-      B = B[:,::-1]
-
-      # Author: Daniel T. McDonald
-
-      I = np.array([0, 1, 2, 3, 15, 16, 32, 64, 128], dtype=np.uint8)
-      np.unpackbits(I[:, np.newaxis], axis=1)
-
-
-
-Adept
-=====
-
-#. Consider an arbitrary array, write a function that extract a subpart with a
-   fixed shape and centered on a given element (pad with a ``fill`` value when
-   necessary)
-
-   .. code :: python
-
-      # Author: Nicolas Rougier
-
-      Z = np.random.random((25,25))
-      shape = (3,3)
-      fill  = 0
-      position = (0,0)
-
-      R = np.ones(shape, dtype=Z.dtype)*fill
-      P  = np.array(list(position)).astype(int)
-      Rs = np.array(list(R.shape)).astype(int)
-      Zs = np.array(list(Z.shape)).astype(int)
-
-      R_start = np.zeros((len(shape),)).astype(int)
-      R_stop  = np.array(list(shape)).astype(int)
-      Z_start = (P-Rs//2)
-      Z_stop  = (P+Rs//2)+Rs%2
-
-      R_start = (R_start - np.minimum(Z_start,0)).tolist()
-      Z_start = (np.maximum(Z_start,0)).tolist()
-      R_stop = np.maximum(R_start, (R_stop - np.maximum(Z_stop-Zs,0))).tolist()
-      Z_stop = (np.minimum(Z_stop,Zs)).tolist()
-
-      r = [slice(start,stop) for start,stop in zip(R_start,R_stop)]
-      z = [slice(start,stop) for start,stop in zip(Z_start,Z_stop)]
-      R[r] = Z[z]
-
-
-
-
-
-
-Expert
-======
-
-#. Consider two arrays A and B of shape (8,3) and (2,2). How to find rows of A
-   that contain elements of each row of B regardless of the order of the elements
-   in B ?
-
-   .. code:: python
-
-      # Author: Gabe Schwartz
-
-      A = np.random.randint(0,5,(8,3))
-      B = np.random.randint(0,5,(2,2))
-
-      C = (A[..., np.newaxis, np.newaxis] == B)
-      rows = (C.sum(axis=(1,2,3)) >= B.shape[1]).nonzero()[0]
-
-
-#. Extract all the contiguous 3x3 blocks from a random 10x10 matrix.
-
-   .. code:: python
-
-      Z = np.random.randint(0,5,(10,10))
-      n = 3
-      i = 1 + (Z.shape[0]-3)
-      j = 1 + (Z.shape[1]-3)
-      C = stride_tricks.as_strided(Z, shape=(i, j, n, n), strides=Z.strides + Z.strides)
-
-
-Master
-======
-
-Archmaster
-==========